x^2+(6/7)x-(1/7)=0

Solution for x^2+(6/7)x-(1/7)=0 equation:

x^2+(6/7)x-(1/7)=0


Domain of the equation: 7)x!=0

x!=0/1

x!=0

x∈R


We add all the numbers together, and all the variables

x^2+(+6/7)x-(+1/7)=0

We multiply parentheses

x^2+6x^2-(+1/7)=0

We get rid of parentheses

x^2+6x^2-1/7=0

We multiply all the terms by the denominator


x^2*7+6x^2*7-1=0

Wy multiply elements

7x^2+42x^2-1=0

We add all the numbers together, and all the variables

49x^2-1=0

a = 49; b = 0; c = -1;
Δ = b2-4ac
Δ = 02-4·49·(-1)
Δ = 196
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{196}=14$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-14}{2*49}=\frac{-14}{98}
=-1/7
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+14}{2*49}=\frac{14}{98}
=1/7
$